Quiz 5 Goals and Resources
[Cutnell/Johnson/Young/Stadler, Physics, 11/e, Chapter 20]
[Quiz 5 worksheet questions (*.pdf)]
- Student Learning Outcomes (in addition to those covered in Quiz 4)
- Reduce series, parallel, and mixed configurations of resistors,
capacitors, and emfs to their appropriate equivalent resistances, capacitances, and emfs, and how Kirchhoff's rules apply differently to series and parallel configurations of resistors, capacitors, and emfs.
- Understand the functionality and proper use of ammeters and voltmeters in idealized and real-world circuits in a laboratory setting.
- Understand the behavior of a "real" battery (with internal resistance).
- Analyze and describe the power dissipated by resistors, or supplied by ideal emfs ("ideal" batteries), or supplied and dissipated by emfs with internal resistance ("real" batteries).
Analyze and describe the time-dependent behavior of charging and discharging RC circuits.
- Understand how household electrical appliances can be approximated as resistive elements wired in parallel with an ideal fixed emf source, and analyze and describe safe and unsafe practices in utilizing household electricity.
- Be able to address and avoid common misconceptions in analyzing circuits (Dennis Albers, cited in Thomas O'Kuma, David P. Maloney, Curtis J. Hieggelke, Ranking Task Exercises in Physics, Prentice Hall (2000), p. 204), such as:
- Whatever lights bulbs grows weaker downstream.
- Whatever lights bulbs is partially used up or weakened by upstream bulbs.
- The leading bulb always has the same brightness regardless of what downstream bulbs exist.
- Current, voltage, and energy are all sort of the same stuff. They flow around the circuit and into bulbs to light them. If the circuit is broken, there is no flow...no current, no voltage, and no energy.
- When a circuit is broken, I = 0. Therefore ΔV = I∙R = 0, and R = 0. That is, there is zero potential difference between points opposite the break.
- Batteries are fixed-current devices. Each battery in series puts out the current it would alone, so the bulb gets only that fixed current. When the batteries are in parallel, the fixed current from each battery joins to form a double current to light the bulb.
- Batteries are fixed-current devices. When there is only one path from the battery to the bulb, the bulb gets that fixed current. When there are two bulbs and two paths (bulbs in parallel), each bulb gets half of that fixed current.
- A jumper wire has essentially R = 0. Therefore, ΔV = I∙R = 0. No voltage suggests no effect, so disregard the jumper wire's presence.
- The more bulbs, the greater the obstacle, hence, the smaller the battery current--regardless of how the bulbs are configured.
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